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Cost: 6 gems
1: Linear Programming
incomplete
2: Profit Function
incomplete
3: Contour Lines
incomplete
4: Simplex Algorithm
incomplete
5: Simplex Algorithm for Solving LP Problems
incomplete
6: Tableau Review
incomplete
7: Simplex Tableau – Slack Variables
incomplete
8: Simplex Tableau – Slack Variables
incomplete
9: Simplex Tableau – Basic Variables and the Solution
incomplete
10: Tableau Solution
incomplete
11: Pivoting the Tableau – When to Stop
incomplete
12: Finding the Pivot Column
incomplete
13: Finding the Pivot Row
incomplete
14: Pivot Row Review
incomplete
15: The Pivot Operation
incomplete
16: Pivot Review
incomplete
17: Solving the Whole Simplex
incomplete
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This lesson's interactive features are locked, please to keep using them
Instead of something reasonable like:
# profit -5x - y = 0
# x <= 250
# y <= 200
# x + y <= 300
ss = SimplexSolver([-5, -1])
ss.add_constraint([1, 0], 250)
ss.add_constraint([0, 1], 200)
ss.add_constraint([1, 1], 300)
What if we tried to solve a problem that had no constraints?
# profit -2x - 3y = 0
# no constraints
ss = SimplexSolver([-2, -3])